Hi, I have a good old scantronic 9600 alarm.
I have an elmdene 16 ohm connected currently works fine and is very loud, however I would like to increase the volume, on reading the manual it says it will drive 2 16 ohm speakers in parallel.

So If I was replace the 16 speaker I have currently and buy an elmdene 8 ohm speaker will I get a louder alarm volume or will it not make a difference? Thanks

ps: I know op's who ask questions on this site have a habit of never getting back to you. But I promise you I will because this is important and would deeply appreciate your feedback. merry christmas

paul, December 2015

thank you

paul, December 2015

Assuming the alarm will drive the same voltage, you will get 2 x the power (Power = V^2/8RL, where V is the output voltage swing peak-to-peak and RL is the load resistance). If I recall correctly, that's about 3dB up (Not actually a lot of audible difference)

Froggo, December 2015

You ask...
So If I was replace the 16 speaker I have currently and buy an elmdene 8 ohm speaker will I get a louder alarm volume or will it not make a difference? Thanks

No you will not get a louder volume - you will get less sound.

The output impedance and the speaker impedance should match - notice the guidance calls for a 16 ohm speaker.

I know noting about alarm systems - I know very little about impedance matching of speakers but enough to warn you to abandon your plan.

Good Luck..., December 2015